EXPERIMENT 104: NEWTON’S SECOND LAW OF MOTION

RESEARCH: NEWTON’S SECOND LAW OF MOTION APPLICATION. Proper squat form:  Begin the movement by pushing your hips and butt out behind you while keeping your back straight. Think “back and out” instead of “up and down”.  Keep your feet flat on the ground(your weight should be shifted to your heels, not your toes).  Begin the descent by pushing your knees forward until your hips/thighs form a parallel line with the floor (think “L” rotated 90 degrees to the right and that’s the shape you should form with your lower body relative to the floor).  Keep your back straight throughout the exercise. Why should you squat? Computation: Table 1 Net force= m2g (0.020 kg)(9.8m/s2 ) = 0.20 N (0.040 kg)(9.8m/s2 ) = 0.39 N (0.060 kg)(9.8m/s2 ) = 0.59 N (0.080 kg)(9.8m/s2 ) = 0.78 N (0.100 kg)(9.8m/s2 ) = 0.98 N Acceleration (accepted value) a= m2 g m1+m2 (0.020 kg)(9.8m/s2 ) 0.5306 kg+0.020 kg = 0.3559 m/s2 (0.040 kg)(9.8m/s2 ) 0.5306 kg+0.040 kg = 0.6869 m/s2 (0.060 kg)(9.8m/s2 ) 0.5306 kg+0.060 kg = 0.9955 m/s2 (0.080 kg)(9.8m/s2 ) 0.5306 kg+0.080 kg = 1.2839 m/s2 (0.100 kg)(9.8m/s2 ) 0.5306 kg+0.100 kg = 1.5540 m/s2 Acceleration (experimental value) a= 2 st2 2(0.50 m) (1.6701s)2 = 0.3585 m/s2 2(0.50m) (1.1903 s)2 = 0.7058 m/s2 2(0.50m) (1.0113 s)2 = 0.9778 m/s2 2(0.50m) (0.8857 s)2 = 1.2748 m/s2 2(0.50 m) (0.7906s)2 = 1.5838 m/s2 Percent error | 0.3585−0.3559 0.3559 |×100 = 1.0115% | 0.7058−0.6869 0.6869 |×100 = 2.7515% | 0.9778−0.9955 0.9955 |×100 = 1.7780% | 1.2748−1.2839 1.2839 |×100 = 0.7088% | 1.5838−1.5540 1.5540 |×100 = 1.9176% Table 2: Acceleration (accepted value) a= m2 g m1+m2 (0.1kg)(9.8m/s2 ) 0.1kg+0.53094 kg = 1.55 m/s2 (0.1 kg)(9.8m/s2 ) 0.1kg+0.63094 kg = 1.34 m/s2 (0.1kg)(9.8m/s2 ) 0.1kg+0.73094 kg = 1.1794 m/s2 (0.1 kg)(9.8m/s2 ) 0.1kg+0.83094 kg = 1.0527 m/s2 (0.1kg)(9.8m/s2 ) 0.1kg+0.93094 kg = 0.9506 m/s2